The its massive size, solar mass and luminosity.

The sun is the main source of light (and some energy) to us humans. It has been around for billions of years and has allowed life on Earth to exist. Most of the things on Earth require light to see and seeing is one of the most useful things to animals and humans. Plants also need light to survive and grow. The sun is at its most basic form a giant radioactive ball of plasma. It constantly shoots energy out of it in the form of solar storms. The formula for calculating the power output of a star is 4n.o.r2T4 where the constant is o (7.16×10 to the -7 power x r to the second power x t to the 4th power). Boltzmann law states that the power emitted by a black body of surface area (A) with a surface temp T (K) is given by the equation. 7.16×10-7r2T4 = 7.16×10-7×6.96x1082x60004 = 7.16×10-7x 4.84x1017x1.296×1015= 4.5×1026 W (this answer was copied and pasted since I wouldn’t figure out how to calculate numbers this large) That number is very large. And that is from the Sun which in galactic standards is normal sized. VY Canis Major is one of the largest stars in the Milky Way and the Observable Universe.This (currently dying) star is not a very powerful one for its massive size, solar mass and luminosity.  It is around 2,000 times the size of our Sun. The surface temperature is 3,490K. The area of this “Hyper Giant” Star is 988.3 million km. Take the surface area and split it in half and you get 494.2 million km. Still a very large number but we aren’t done yet. We have to square that number so if we take 494.2 million x 494.2 million you will get a number that looks like this 2.2413481e+19 (A). Then we take the surface temp of 3,490K and times it by itself 4 times to get 1.4835484e+14 (T). Then we multiply those numbers together to get 9.038690438894 to the 26th power. We are now ready to solve how much energy VY Canis Major spews out. (Keep in mind that the star’s temperature directly affects the amount of energy it will be releasing at 1 moment in time) 7.16×10 to the -7th power x 9.03 to the 26th power 2 x 3,490K=1.49×10 to the 33rd power watts. That is 1.49 decillion watts of energy! The reason that VY Canis Major is not putting out a major electrical charge is because the fact of that it is currently in the “dying” phase of its life. It has used up most of its hydrogen during its mid-life phase and is now very close (in cosmological standards) close to supernova.   The Milky Way has been proven to have around 100 billion stars based on the solar mass of 100 billion. Most of those stars though are usually white dwarfs. Around 98% of the Milky Way is white dwarf stars. These stars are usually around 8 times smaller and but more than 3000x denser than the Sun. These stars have a lifespan thought to have been longer than the Universe’s current age (13.6 billion years). We will still be using the main formula (as shown in paragraph 1) to solve this problem too. White dwarfs are as dense as the Sun but contained in an area the size of Earth. Earth has a radius of 3,959 km. So we will just use the Earth measurement. The surface temperature is between 8,000 and 16,000K. I will go directly in the middle and use 12,000K as my surface temp. So we will be taking 3,959 x 3,959 to get the squared amount of 15,673,681. We will add up the answers for our 2 variables to get our final variable of 2.88e to the power of 14. 7.16×10 to the power of -7 x 2.88e+14 2x 12,000 to the 4th power = 5.15e+16 watts. That is 5.15 quadrillion watts of power coming from just ONE white dwarf. Stars are some of the largest forms of “reactors” in a sense giving off massive amounts of energy as they feed off of their massive amounts of hydrogen and helium hidden deep within the recesses of space. Hydrogen and helium are what all stars feed off of during their massive lifespan and they are very good sources of energy. Hydrogen is a very good fuel source giving off 144,000 joules of energy per kilogram of hydrogen. Stars are made up of quadrillions upon quadrillions of kilograms of hydrogen, helium and plasma. Stars usually are around 0.7% energy efficient and will almost never use more than 10% of its stored hydrogen supply but massive stars can use up all available hydrogen and helium and since it is so massive it can still fuse heavy elements and its core will turn to iron and could possibly go supernova or hypernova depending on the size and mass of the star. Since we are on the topic of supernovae we will begin to discuss how much energy those release and compare to that when they were “alive”. Based on the research done scrolling through many science websites the total estimated energy released during a supernova for a star the size of our sun would be 10 to the 44th power joules. That is more energy than the Sun releases during its entire lifespan in just one second at its peak. the Milky Way galaxy (even though on the cosmic scale the Milky Way is one of the smallest galaxies). Our galaxy is filled to the brim with white dwarfs and red giants in some places so our galaxy doesn’t output much power compared to our nearest neighbor the Andromeda Galaxy that is set to collide with our galaxy in about 200 million years. But from doing a little bit of digging I have found the answer of  4×10 to the 58th power,